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Organic Chemistry · Class XII · 2025-26

Named Reactions

30+ essential named reactions with reagents, equations, and CBSE exam patterns.

🔗 Key Conversion Chains

CH₄ Cl₂/hν CH₃Cl NaOH(aq) CH₃OH PCC/K₂Cr₂O₇ HCHO KMnO₄ HCOOH
C₆H₆ Br₂/FeBr₃ C₆H₅Br NH₃/CuBr C₆H₅NH₂ NaNO₂/HCl, 0–5°C C₆H₅N₂⁺Cl⁻ H₂O/H⁺ C₆H₅OH
CH₃CH₂OH K₂Cr₂O₇/H⁺ CH₃COOH SOCl₂ CH₃COCl NH₃ CH₃CONH₂ Br₂/NaOH CH₃NH₂
🟣 Haloalkanes & Haloarenes 5 reactions
Memory tip Finkelstein uses NaI/acetone (NaCl insoluble → drives forward). Swarts uses AgF. Wurtz doubles the chain (2 RX → R-R).
Finkelstein Reaction
NaI, dry acetone, reflux
R–Cl + NaI → R–I + NaCl↓
💡 Driving force: NaCl is insoluble in acetone → precipitates out → equilibrium shifts forward. Converts RCl/RBr → RI.
Asked as: "What is Finkelstein reaction? State the driving force." [2 marks]
Swarts Reaction
AgF or CoF₂ or SbF₃
R–Cl + AgF → R–F + AgCl↓
💡 Used to prepare alkyl fluorides (RF) which cannot be made directly from alkene + HF easily. AgCl precipitates → drives forward.
Asked as: "How are alkyl fluorides prepared?" [1–2 marks]
Wurtz Reaction
Na, dry ether
2R–X + 2Na → R–R + 2NaX
💡 Doubles the carbon chain. Only useful for symmetrical alkanes (same R on both sides). Limitation: 2 different RX gives mixture of 3 products.
Asked as: "How is ethane prepared from methyl iodide?" [1–2 marks]
Wurtz–Fittig Reaction
Na, dry ether
R–X + ArX + 2Na → R–Ar + 2NaX
💡 Coupling of alkyl halide with aryl halide. Gives alkylbenzene. Example: CH₃Br + C₆H₅Br + 2Na → CH₃C₆H₅ (toluene) + 2NaBr.
Asked as: "Distinguish Wurtz and Wurtz-Fittig reactions." [2 marks]
Fittig Reaction
Na, dry ether
2ArX + 2Na → Ar–Ar + 2NaX
💡 Coupling of two aryl halides → biphenyl type product. Example: 2C₆H₅Br + 2Na → C₆H₅–C₆H₅ + 2NaBr.
Asked as: "How is biphenyl prepared?" [1 mark]
🔵 Alcohols, Phenols & Ethers 5 reactions
Memory tip Kolbe uses CO₂ (needs pressure). Reimer-Tiemann uses CHCl₃ (gives CHO). Williamson makes ethers by SN2 (needs alkoxide + alkyl halide).
Kolbe's Reaction
CO₂, 300°C, 5 atm → then H⁺
C₆H₅ONa + CO₂ → C₆H₅OH·COONa → salicylate (sodium phenoxide → sodium salicylate)
💡 Phenol converted to sodium phenoxide, then carboxylated. Product is sodium salicylate (aspirin precursor). High pressure required.
Asked as: "How is salicylic acid prepared from phenol?" [2 marks]
Reimer–Tiemann Reaction
CHCl₃, NaOH, then H₃O⁺
C₆H₅OH + CHCl₃ + 3NaOH → o-HO-C₆H₄-CHO (salicylaldehyde / o-hydroxybenzaldehyde)
💡 Introduces −CHO group ortho to −OH. Mechanism: CHCl₃ + NaOH → dichlorocarbene (:CCl₂) which attacks ring. Mainly ortho product.
Asked as: "How is salicylaldehyde prepared?" [2 marks]
Williamson's Ether Synthesis
Alkoxide + alkyl halide (SN2)
R–O⁻Na⁺ + R'–X → R–O–R' + NaX
💡 Best method to make unsymmetrical ethers. SN2 mechanism → use primary alkyl halide with bulky alkoxide (tertiary alkyl halide gives elimination).
Asked as: "How is methyl ethyl ether prepared by Williamson's synthesis?" [2 marks]
Lucas Test
ZnCl₂ + conc. HCl (Lucas reagent)
3° R-OH → turbidity immediately 2° R-OH → turbidity in ~5 min 1° R-OH → no turbidity at RT
💡 Turbidity = RCl (insoluble in reagent). 3° fastest via SN1. Distinguishes primary/secondary/tertiary alcohols.
Asked as: "How do you distinguish 1°, 2° and 3° alcohols chemically?" [3 marks]
Victor Meyer Test
P/I₂ → HNO₂ → KOH → NaOH
1° → red colour (nitroso compound) 2° → blue colour 3° → colourless
💡 Converts alcohol → iodoalkane → nitroalkane → reaction with HNO₂. 1°: nitroso compound + NaOH → red. 2°: blue complex. 3°: no α-H → no colour.
Asked as: "How does Victor Meyer test distinguish 1°/2°/3° alcohols?" [3 marks]
🔴 Aldehydes, Ketones & Carboxylic Acids 10 reactions
Memory tip Aldol needs α-H + dilute NaOH. Cannizzaro = no α-H + conc. NaOH. Tollens = silver mirror (aldehydes only). Fehling = brick red (aliphatic aldehydes only). HVZ = α-bromination of acids.
Aldol Condensation
Dilute NaOH (or dilute acid), warm
2CH₃CHO → CH₃CH(OH)CH₂CHO ↓ (−H₂O, heat) CH₃CH=CHCHO (crotonaldehyde)
💡 Requires α-H. Step 1: nucleophilic addition → β-hydroxy carbonyl (aldol product). Step 2: dehydration → α,β-unsaturated carbonyl. Cross aldol possible (two different carbonyl compounds).
Asked as: "Give the mechanism of aldol condensation of acetaldehyde." [3–5 marks]
Cannizzaro Reaction
Conc. NaOH
2HCHO + NaOH → CH₃OH + HCOONa 2PhCHO + NaOH → PhCH₂OH + PhCOONa
💡 ONLY for aldehydes with NO α-H (HCHO, PhCHO, (CH₃)₃CCHO). Disproportionation: one molecule oxidised (→ acid), one reduced (→ alcohol). Mechanism: hydride transfer.
Asked as: "Distinguish Cannizzaro from Aldol. When does Cannizzaro occur?" [3–5 marks]
Tollens' Test (Silver Mirror)
[Ag(NH₃)₂]⁺OH⁻ (Tollens' reagent), warm
RCHO + 2[Ag(NH₃)₂]⁺ + 2OH⁻ → RCOO⁻ + 2Ag↓ + 4NH₃ + H₂O
💡 Silver mirror formed on glass. Positive for: all aldehydes (RCHO), formic acid (HCOOH), glucose. Negative for: ketones, benzaldehyde does give positive.
Asked as: "How do you distinguish aldehyde from ketone?" [2 marks]
Fehling's Test
Fehling's solution (A + B), heat
RCHO + 2Cu²⁺ + 4OH⁻ → RCOO⁻ + Cu₂O↓(brick red) + 2H₂O
💡 Brick-red ppt of Cu₂O. Positive for: aliphatic aldehydes, glucose, fructose. Negative for: aromatic aldehydes (benzaldehyde), ketones. More selective than Tollens.
Asked as: "Why does benzaldehyde not give Fehling test?" [2 marks]
Clemmensen Reduction
Zn(Hg) amalgam + conc. HCl, reflux
>C=O + 4[H] → >CH₂ + H₂O
💡 Reduces carbonyl (C=O) to methylene (CH₂). Acid-sensitive compounds: use Wolff-Kishner instead. Used for: PhCOCH₃ → PhCH₂CH₃.
Asked as: "How is toluene prepared from acetophenone?" [2 marks]
Wolff–Kishner Reduction
H₂N–NH₂ (hydrazine), KOH, ethylene glycol, heat
>C=O + H₂NNH₂ → >C=NNH₂ + H₂O → >CH₂ + N₂
💡 Complementary to Clemmensen. Used for base-stable, acid-sensitive substrates. Hydrazone intermediate decomposes to give N₂ gas (driving force).
Asked as: "Compare Clemmensen and Wolff-Kishner reductions." [3 marks]
Hell–Volhard–Zelinsky (HVZ)
Br₂ + PCl₃ (or red P), then H₂O
RCOOH + Br₂ → RCH(Br)COOH + HBr (α-bromo carboxylic acid)
💡 α-halogenation of carboxylic acids. Not possible directly with Br₂ alone; PCl₃ activates acid to acyl chloride first. Product: α-bromocarboxylic acid.
Asked as: "How is α-bromopropionic acid prepared from propionic acid?" [2 marks]
Rosenmund Reduction
H₂, Pd/BaSO₄ catalyst (poisoned Pd), xylene
RCOCl + H₂ → RCHO + HCl
💡 Selective reduction of acyl chloride → aldehyde (stops before alcohol). BaSO₄ poisons Pd to prevent over-reduction. Quinoline-S further deactivates catalyst.
Asked as: "How is benzaldehyde prepared from benzoyl chloride?" [2 marks]
Stephen's Reduction
SnCl₂ + HCl, then H₂O
RCN + SnCl₂ + HCl → [RCH=NH] → RCHO
💡 Nitrile (RCN) → aldehyde (RCHO). Mechanism via imine intermediate which hydrolyses to aldehyde. Useful for aromatic aldehydes from aromatic nitriles.
Asked as: "How is benzaldehyde prepared from benzonitrile?" [2 marks]
Etard Reaction
CrO₂Cl₂ (chromyl chloride), CS₂
C₆H₅–CH₃ + 2CrO₂Cl₂ → [complex] → C₆H₅CHO
💡 Selective oxidation of methyl group on benzene ring to aldehyde. Chromyl chloride is a specific reagent for this transformation.
Asked as: "How is benzaldehyde prepared from toluene?" [2 marks]
🟣 Amines 7 reactions
Memory tip Gabriel makes only 1° amine (phthalimide route). Hofmann = lose 1 carbon (RCONH₂ → RNH₂). Carbylamine = smelly isocyanide = test for 1°. Diazotisation always 0–5°C.
Gabriel Synthesis
KOH → then R-X → then H₂NNH₂ or acid hydrolysis
Phthalimide + KOH → potassium phthalimide + RX → N-alkylphthalimide + H₂NNH₂ → R–NH₂ + phthalhydrazide
💡 Gives ONLY primary aliphatic amines (no 2° or 3°). Cannot be used for aromatic amines (ArX won't undergo SN2 with nitrogen nucleophile).
Asked as: "How is methylamine prepared by Gabriel synthesis?" [3–5 marks]
Hofmann Bromamide Degradation
Br₂ + NaOH (aqueous)
RCONH₂ + Br₂ + 4NaOH → R–NH₂ + Na₂CO₃ + 2NaBr + 2H₂O
💡 Product has ONE LESS carbon than starting amide (R loses CO). Gives pure primary amine. Mechanism: N-bromoamide → isocyanate → amine.
Asked as: "How is methylamine prepared from acetamide?" [3 marks]
Diazotisation
NaNO₂ + HCl, 0–5°C
ArNH₂ + NaNO₂ + 2HCl → ArN₂⁺Cl⁻ + NaCl + 2H₂O (diazonium salt)
💡 Temperature CRITICAL (0–5°C): diazonium salts decompose above 5°C. Only primary aromatic amines. Diazonium salt is highly useful for synthesis.
Asked as: "What is diazotisation? Give conditions." [2 marks]
Coupling Reaction (Azo Dye Formation)
Diazonium salt + activated aromatic compound, alkaline medium
ArN₂⁺ + C₆H₅OH → Ar–N=N–C₆H₄–OH + H⁺ (orange-red azo dye)
💡 Electrophilic substitution at para position of phenol/aniline. Always occurs in para position preferentially. Azo group (–N=N–) is chromophore (gives colour).
Asked as: "How is orange azo dye prepared?" [2–3 marks]
Carbylamine Reaction
CHCl₃ + KOH (alcoholic), heat
R–NH₂ + CHCl₃ + 3KOH → R–N≡C + 3KCl + 3H₂O (isocyanide — foul smell)
💡 Confirmatory test for PRIMARY amines (both aliphatic and aromatic). 2° and 3° amines do NOT give this test. Mechanism: dichlorocarbene attacks amine.
Asked as: "How do you confirm presence of primary amine?" [2 marks]
Hinsberg's Test
C₆H₅SO₂Cl (benzenesulfonyl chloride)
1°: R-NH₂ → sulfonamide (soluble in NaOH) 2°: R₂NH → sulfonamide (insoluble in NaOH) 3°: R₃N → no reaction
💡 1° product has N–H → acidic, dissolves in NaOH. 2° product has no N–H → insoluble ppt. 3° can't react (no N–H). Best test to distinguish 1°/2°/3° amines.
Asked as: "How does Hinsberg test distinguish 1°, 2°, 3° amines?" [3–5 marks]
Acetylation of Amines
Acetic anhydride or acetyl chloride
R–NH₂ + (CH₃CO)₂O → R–NHCOCH₃ + CH₃COOH
💡 Protects amine group. Used in synthesis to reduce reactivity of amine (e.g., aniline → acetanilide before nitration to avoid over-reaction). Reversed by hydrolysis.
Asked as: "Why is aniline acetylated before nitration?" [2 marks]
⚗️ Diazonium Salt Reactions (Cross-Chapter) 5 reactions
Memory tip Sandmeyer uses Cu halide. Gattermann uses Cu metal + acid (cheaper). Balz-Schiemann uses BF₄⁻ → gives ArF. All start from diazonium salt (ArN₂⁺).
Sandmeyer Reaction
CuCl/CuBr/CuCN (cuprous halide)
ArN₂⁺Cl⁻ + CuCl → ArCl + N₂ + CuCl ArN₂⁺Cl⁻ + CuBr → ArBr + N₂ ArN₂⁺Cl⁻ + CuCN → ArCN + N₂
💡 Replaces N₂ group with halide or CN. Uses cuprous salt. Important for introducing Cl/Br/CN into benzene ring without using Friedel-Crafts (which has limitations).
Asked as: "How is chlorobenzene/bromobenzene prepared from benzene?" [3 marks]
Gattermann Reaction
Cu powder + HCl or HBr
ArN₂⁺Cl⁻ + HCl + Cu → ArCl + N₂ + CuCl
💡 Similar to Sandmeyer but uses Cu metal instead of CuX. Less efficient but cheaper. Cu acts as reducing agent and catalyst.
Asked as: "Distinguish Sandmeyer and Gattermann reactions." [2 marks]
Balz–Schiemann Reaction
HBF₄ → then heat
ArN₂⁺Cl⁻ + HBF₄ → ArN₂⁺BF₄⁻ ArN₂⁺BF₄⁻ → ArF + N₂ + BF₃ (on heating)
💡 Only way to introduce F into benzene ring via diazonium salt. Diazonium fluoroborate is stable solid; decomposes on heating to give aryl fluoride.
Asked as: "How is fluorobenzene prepared from aniline?" [2 marks]
Replacement by OH (Hydrolysis)
H₂O, H⁺ (dilute H₂SO₄), warm
ArN₂⁺ + H₂O → ArOH + N₂ + H⁺
💡 Converts aniline → phenol via diazonium salt. Better route than direct hydroxylation of benzene. Diazonium salt solution warmed with dilute acid.
Asked as: "How is phenol prepared from aniline?" [2 marks]
Replacement by H (Deamination)
H₃PO₂ (hypophosphorous acid)
ArN₂⁺Cl⁻ + H₃PO₂ + H₂O → ArH + N₂ + H₃PO₃ + HCl
💡 Removes N₂ group and replaces with H. Useful for making compounds that cannot be obtained by direct substitution (e.g., 1,3,5-tribromobenzene from 2,4,6-tribromoaniline).
Asked as: "How is 1,3,5-tribromobenzene prepared?" [3 marks]